Question

A paper in the form form of a retangle length 88cm and breadth 20cm. This is folded to form a cylinder.find its volume and outer surface area?​

Answer 1

Answer:

$\huge{\boxed{\boxed{\sf{Volume=12320cm^{3}}}}}$

$\huge{\boxed{\boxed{\sf{T.S.A=1496cm^{2}}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

□Length of rectangle=88cm

□Breadth of rectangle=20cm

>>fold this paper along breadth so that

☆circumference of circle=88cm

$2\pi r = 88cm \\ 2 \times \frac{22}{7} \times r = 88 \\ r = \frac{88 \times 7}{2 \times 22} \\ r = \frac{28}{2} \\ r= 14cm$

□radius=14cm

□height=20cm

☆Volume of cylinder

$\pi {r}^{2} h = \frac{22}{7} \times 14 \times 14 \times 20 \\ = )44 \times 14 \times 20 \\ = )12320 {cm}^{3}$

☆Total surface area of cylinder

$\pi r(h + r) \\ = ) \frac{22}{7} \times 14(20 + 14) \\ = )44 \times 34 \\ = )1496 {cm}^{2}$

$\huge{\boxed{\boxed{\sf{Volume=12320cm^{3}}}}}$

$\huge{\boxed{\boxed{\sf{T.S.A=1496cm^{2}}}}}$

Answer 2

Answer:

Volume = 12320 cm³

TSA = 1496 cm²

Step-by-step explanation:

Hope it helps you