Question

A paper is in the form of a rectangle PQRS in which
PQ = 10 cm and QR = 7 cm. Two semi-circular portions
with QR and PS as diameters are cut off (As shown in
figure 11.22). Find the area of the remaining part.​

Answer 1

Answer:

$as given \: in \: paper \: the \: answer \: must \: be \: same \:$

Answer 2

Step-by-step explanation:

In rectangle the breadth of the rectangle is the diameter of circle(r=d/2).

Radius of the circle=7/2.

A.T.Q:-

Area of the remaining portion=

area of rectangle - area of two semi-circle.

=L×B-2πR^2

=L×B-πR^2------(i)

L=10 cm

B=7 cm

R=7/2 cm

Put all the values in (i)

=L×B-πR^2

=10×7-22/7×7/2×7/2

=70-77/2

=70-38.5

=31.5 cm