a paper is in the form of a rectangle pqrs in which PQ is equal to 10 centimetre and you are is equal to 7 cm two semi circular motions with q r and ps as diameters are cut off find the area of the remaining part
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area of ramaining part = area of rectangle - area of 2 semicircles of diameter 7cm
=10*7 - 22/7 * 7/2 *7/2
= 70-77/2
=( 140 - 77 )/2
= 63/2
= 21.5
=10*7 - 22/7 * 7/2 *7/2
= 70-77/2
=( 140 - 77 )/2
= 63/2
= 21.5
Answered by
1
area of rectangle is 70cm.
1÷2×πrsqaure
11÷7×3.5×3.5
11×0.5×3.5
19.25
19.5 + 19.5
39
area of remaining part =70-39
=31cmsquare
1÷2×πrsqaure
11÷7×3.5×3.5
11×0.5×3.5
19.25
19.5 + 19.5
39
area of remaining part =70-39
=31cmsquare
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