Question

A paper is in the form of rectangle having length 28 cm and breadth 21 cm. A semicircular portion with breadth as a diameter is cut off. The area of remaining portion is

Answer 1

Step-by-step explanation:

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Answer 2

MATHS

A paper is in the form of a rectangle ABCD in which AB=30cm and DA=20cm. A semicircular portion with BC as diameter is cut off.Find the area of the remaining part.

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December 27, 2019avatar

Sabby Sanathra

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ANSWER

We have,

AB=CD=30 cm

AD=BC=20 cm

Since,

ABCD is a rectangle and semicircular portion with BC diameter is cut off. it means radius of semicircle is 10 cm.

Therefore, the area of remaining part is

=AB×AD−

2

π×(BC/2)

2

=30×20−

2

π×(20/2)

2

=600−

2

π×(10)

2

=600−

2

π×100

=600−3.14×50

=600−157

=443 cm

2

Hence, this is the answer.