Question

a paper protractor of radius 14cm is bent into an open conical cup. then find the depth and volume of the cup

Answer 1

The base of the cup will be a circle whose circumference is equal to the circumference of the semicircle and the slant height of the cone is equal to the radius of the cone.

We can use pythogras theorem to get the height of the cone.

14^2 - 14^2=147

H=12.12

VOLUME=1/3 × pi × h × r2

0.3333×3.142×12.12× 7×7=621.93cm3