A parachutist after bailing out falls for 10s
without friction. When the parachute opens
he descends with an acceleration of 2 m/s?
against his direction and reached the ground
with 4 m/s. From what height he has dropped
himself? (g=10m/s)
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Answer:
⇒u=gt
⇒u=10g
h1=12gt2
h2=ν2−u2−2a
total height =h1+h2
After Solving we Get Distance 2996m.
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