Question

A parachutist drops freely from an aeroplane for 10s before the parachute opens out. Then he descends with a net retardation of 2.5 m/s2: If he bails out of the plane at a height of 2495 m and g = 10 m/sec?, his velocity on reaching the ground will be : (1) 5 m/s (2) 10 m/s (3) 15 m/s (4) 20 m/s​. please give answer to me please

Answer 1

Answer: is Option (A) 5$m/s^{2}$

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Explanation:

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u=0m/s

a=g=10$m/s^{2}$ (Free fall body)

t=10seconds

v=u+at

v=0+10*10

=>v=100m/s=v1

$s=ut+1/2at^2$

s=0.t+1/2*10*10*10

s=500m

distance covered = (2495-500)m=1995

a=2/5$m/s^{2}$ (after retardation)

$v^2-v1^2=2as$

$v^2-(100)^2=2*2.5*1995$  

$v^2=10000-9975\\v^2=25\\v=5m/s^2$