Question

A Parachutist of weight W strikes the ground with his legs fixed and come to rest with an upward acceleration of magnitude 3g. Force exerted on him by the ground during landing is ?

Answer 1

Answer:

Answer: 4W

Explanation:

"

F = mg.

This formula is used to calculate the force with which an object is pulled towards the earth , here F – force which is pulling the object

m- mass of the object, this is usually in grams

g- gravity or the gravitational force

As per the question

Mg = M (g+3g)

4mg

4W

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Answer 2

Answer:4 W

Explanation:

Given

Parachutist of weight W strikes the earth ground with legs with an upward acceleration of magnitude 3g.

First Normal Force will cancel the gravity g and then applies force to produce an upward acceleration of 3g i.e. total of 4g acceleration upward

mass of parachutist$=\frac{W}{g}$

Normal Force$=\frac{W}{g}\times 4g=4W$

Thus a total of 4 W force is exerted by parachutist on ground is 4 W