Question

A parallel arrangement of 3 and 6 ohm resistors is placed in series with a
4-ohm resistor. If a p.d. of 30 V is connected across the whole circuit, calculate
the voltage across the parallel arrangement.

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

voltage across the parallel arrangement of resistances=10 volts

Explanation:

Given,

A parallel arrangement of 3 and 6 ohm resistors is placed in series with a

4-ohm resistor.

3 and 6 ohm resistors connected in parallel

=$\frac{1}{R_{eq} }= \frac{1}{3} +\frac{1}{6} \\ \\ \\= \frac{3}{6} \\ \\= \frac{1}{2} \\R_{eq}=2 ohms$ (resistance at parallel arrangement)

now

4 ohms and 2 ohms connected in series

Rs=4+2=6 ohms

total current in circuit I=$\frac{v}{R_{s} } =\frac{30}{6}$

I=5Amps

voltage across the parallel arrangement v=IR

                                                                      =5*2

                                                                       =10 volts

voltage across the parallel arrangement of resistances=10 volts    

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