Question

A parallel beam of light in incident on a liquid surface such that the wave front makes an angle 30o with the surface and has a width of 3 m, the width of the refracted beam is_______ (aμL=3 )

(please I want detailed solution..with diagram.. I will mark as brainlist answer)​

Answer 1

Given:

incidence angle i = 30°

width of incident beam w$_i$ = 3 m

To find:

the width of the refracted beam w$_r$ =?

Step-to-step-explanation:

• The beam of light is incident on the surface of a parallel beam. It makes an angle of 30° with a beam.

        i.e. i = 90° - 30° = 60°

• The angle of incidence & angle of refraction is complementary.

         i + r =90°

         60° + r = 90°

         r = 30°

• we know that,

          $\displaystyle \frac{W_i}{W_r}=\frac{cos\ i}{cos\ r}$

         $\displaystyle \frac{3}{W_r}=\frac{cos\ 60}{cos\ 30}$

w$_r$ = 5.1961 m

• The width of the refracted beam is 5.1961 m.