if these are the angles, then find x and y
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as AB ||DE
angle ABD= angle EDC=x°
again , angle AED+angle DEC=180°
= > 95+angle DEC=190
=> angle DEC=(180-95)°=85°
in triangle DEC
angle EDC+angle DCE+ angleDEC=180
=> angle EDC={180-(40+85)}°=(180-125)°=55°
so, angle EDC=angle ABD=55°
angle EDB==(180-55)°=125°
so angle BAE={360-(95+125+55)}°
=(360-275)°=85°
so anglebFAE=y=(180-85)°=95°
so , x=55° , y=95°
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