Question

A parallel beam of light of intensity i is incident normally

Answer 1

Answer:

then the refleced angles is 0

Answer 2

Answer:

5.33×108N

Solution :

Momentum of incident light, per sec.,

p1=Ec=103×108

Momentum of the reflected ligher per sec.

p2=60100×Ec=60100×103×108

∴ Force on the surface =change in momentum per sec

=p2−(−p1)=p2+p1

=60100×103×108+103×108=5.33×10−8N