Question

a parallel network consists of three resistors of 4 ohm ,8 ohm and 16 ohm . if current through the 8 ohm resistor is 3A .calculate the current through other resistors ​

Answer 1

Answer:

current through 4ohm resistor = 24/4 = 6A

current through 16ohm resistor = 24/16 = 1.5A

Step-by-step explanation:

V = I*R

V = 3*8

V = 24v

I = V/R

current through 4ohm resistor = 24/4 = 6A

current through 16ohm resistor = 24/16 = 1.5A

Answer 2

✯ Aɴsᴡᴇʀ

we have,

• 3 resistors of 4 ohm , 8 ohm and 16 ohm connected in parallel

• V = Voltage or potential difference
• I = current
• R = resistance

by ohm's law

• V = IR

☯︎ so for resistor of 8 ohm

V = IR

V = 3 × 8

➪ V = 24 Volt

and we know that, in parallel combination of resistance potential difference act is same across all resistors.

➪ V = 24 Volt

now,

☯︎ for resistor of 4 ohm

V = IR

➪ 24 = I × 4

➪ I = 24/4

➪ I = 6 A

☯︎ for resistor of 16 ohm

V = IR

➪ 24 = I × 16

➪ I = 24/16

➪ I = 3/2

➪ I = 1.5 A

therefore, current passing through

• resistor of 4 ohm is 6 Ampere
• resistor of 16 ohm is 1.5 Ampere