a parallel network consists of three resistors of 4 ohm ,8 ohm and 16 ohm . if current through the 8 ohm resistor is 3A .calculate the current through other resistors
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Answered by
4
Answer:
current through 4ohm resistor = 24/4 = 6A
current through 16ohm resistor = 24/16 = 1.5A
Step-by-step explanation:
V = I*R
V = 3*8
V = 24v
I = V/R
current through 4ohm resistor = 24/4 = 6A
current through 16ohm resistor = 24/16 = 1.5A
Answered by
70
✯ Aɴsᴡᴇʀ
we have,
- 3 resistors of 4 ohm , 8 ohm and 16 ohm connected in parallel
- V = Voltage or potential difference
- I = current
- R = resistance
by ohm's law
• V = IR
☯︎ so for resistor of 8 ohm
V = IR
V = 3 × 8
➪ V = 24 Volt
and we know that, in parallel combination of resistance potential difference act is same across all resistors.
➪ V = 24 Volt
now,
☯︎ for resistor of 4 ohm
V = IR
➪ 24 = I × 4
➪ I = 24/4
➪ I = 6 A
☯︎ for resistor of 16 ohm
V = IR
➪ 24 = I × 16
➪ I = 24/16
➪ I = 3/2
➪ I = 1.5 A
therefore, current passing through
- resistor of 4 ohm is 6 Ampere
- resistor of 16 ohm is 1.5 Ampere
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