Question

A parallel plate capacitor has an area of 4 cm2 and a plate separation of 2 mm. Calculate its
capacitance.
Given E⁰ = 8.85 x 10^-12 c2/Nm2​

Answer 1

Answer:

1.77 x 10⁻¹² F

Explanation:

Area = 4 cm² = 4 (1/100 m)²

                      = 4 x 10⁻⁴ m²

Distance = 2 mm = 2 x 10⁻³ m

   Using, C = ε₀A/d

C = (8.85 x 10⁻¹² x 4 x 10⁻⁴)/2 x 10⁻³

   = 1.77 10⁻¹² F

Answer 2

Given:

A parallel plate capacitor has an area of 4 cm² and a plate separation of 2 mm.

To find:

Capacitance value ?

Calculation:

The general expression of capacitance of parallel plate capacitor is :

$C = \dfrac{A \epsilon_{0} }{d}$

• Here A = 4 cm² = 4 × 10^(-4) m².

• Also, d = 2 mm = 2 × 10^(-3) m

$\implies C = \dfrac{(4 \times {10}^{ - 4} ) \times 8.85 \times {10}^{ - 12} }{2 \times {10}^{ - 3} }$

$\implies C = 17.7\times {10}^{ - 11} \: F$

So, capacitance is 17.7 × 10^(-11) Farad.