A parallel plate capacitor has played area of 16 minus 3 square in operation of 3 metre potential difference of hundred volt is established between the place where battery after disconnecting the battery space between the plates is filled by three in millimetre thick mika sheet of dielectric constant k is equals to 6 find the potential difference between the plates define capacitance and the final charge on the capacitor
Answers
Answer:
The capacitance of multiple parallel plate capacitor can be calculated as: where A = Area of each plate; ε0 = Relative Permittivity of a Vacuum = 8.854 × 10-12 F/m; εr = Relative Permittivity of Dielectric; D = Distance between plates; N = Number of Plates.
The generalised equation for the capacitance of a parallel plate capacitor is given as: C = ε(A/d) where ε represents the absolute permittivity of the dielectric material being used.
Adding a dielectric allows the capacitor to store more charge for a given potential difference. When a dielectric is inserted into a charged capacitor, the dielectric is polarized by the field. The electric field from the dielectric will partially cancel the electric field from the charge on the capacitor plates.