A parallel plate capacitor is charged and kept connected with the battery. If now a dielectric slab is inserted between the plates to fill the entire space between the plates then what will be the change in the charge, potential difference and electric field intensity between the plates respectively (A) increases , constant, increases (B) increases, constant , constant (C) increases , constant , decreases (D) constant, decreases , deccrase
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Hii Mate....
I think (D) constant, decreases , Decrease
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