A parallel-plate capacitor is
charged to electric
potential of 305 V by
moving 3.75 10^16
electrons from one plate to
the other. How much work
is done in charging the
capacitor?
9 J
2 J
O 0.215 J
0.915 J
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Given info : A parallel-plate capacitor is charged to electric potential of 305 volts by moving 3.75 × 10¹⁶ electrons from one plate to the other.
To find : How much work is done in charging the capacitor.
solution : work done to charge the capacitor , W = qV/2
where q = total charge transferred from one plate to the other
V = electric potential
here q = 3.75 × 10^16 × 1.6 × 10^-19 C [ we know charge on each electron is 1.6 × 10^-19 C]
= 6 × 10^-3 C
and V = 305 volts.
now work done , W = 1/2 qV = 6 × 10^-3 C × 305 volts
= 3 × 305 × 10^-3 J
= 0.915 J
Therefore 0.915 J work is done in charging the capacitor.
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