Physics, asked by cyril19, 9 months ago

A parallel-plate capacitor is placed in such a way that
lates are horizontal and the lower plate is dipped
into a liquid of dielectric constant K and density p. Each
plate has an area A. The plates are now connected to a
battery which supplies a positive charge of magnitude Q
to the upper plate. Find the rise in the level of the liquid
in the space between the plates.
+
+
+
+
+
+
+_
+C -0(1-1/K)
= -QK
Figure 31-W16​

Answers

Answered by Anonymous
0

Answer:

parallel-plate capacitor is placed in such a way that its plates are horizontal and the lower plate is dipped into a liquid of dielectric constant

and density

. Each plate has an area

. The plates are now connected to a battery which supplies a positive charge of magnitude

to the upper plate. Find the rise in the level of the liquid in the space between the

Explanation:

Answered by aryanamma1704
0

Answer:sigma square*(k^2-1)/2epsilonrho g

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