A parallel--plate capacitor with air between the plates has an area A=2×104m2 and a plate separation d=1 mm. What is its capacitance?
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Answer:
Answer
Area of each plate A=6×10
−3
m
2
Distance between the plates d=3mm=0.003m
Capacitance of capacitor C=
d
Aϵ
o
∴ C=
0.003
6×10
−3
×8.85×10
−12
=17.7pF
Voltage across the capacitor V=100 volts
Thus charge on each plate Q=CV
∴ Q=17.7×10
−12
×100
⟹ Q=1.77×10
−9
C
Explanation:
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