Question

A parallel plate capacitor with air gap of 5 mm is 2 MFD. If a metallic plate of thickness
3 mm is inserted in between the plates, the new capacitance is

Answer 1

data :

d1 = 5 * 10^-3 m

C1 = 2 * 10^-6 F

d2 = 3 * 10^-3 m

C2 =?

since C is inversaly proportional to d there fore

C1 * d1 = C2 * d2

now solve it you will get the answer

Answer 2

Answer:

The new capacitance is 3.33MFD

Explanation:

D1 = 5 mm

= 5× 10-³ m

D2= 3mm

= 3×10-³m

C1 = 2MFD

= 2×10-⁶ F

D1C1= D2C2

C2 = D1× C1

D2

= 5×10-³×2×10-⁶

3×10-³

=10 × 10-⁶

3

= 3.33×10-⁶F

=3.33MFD