Question

A parallel plate capacitor with plate area A and plate separation d, is filled with a dielectric slab as shown . What is the capacitance of the arrangement

Answer 1

Explanation:

parallel plate capacitor of area A, plate separation d and capacitance C is filled with three different dielectric materials having dielectric

Answer 2

$C=k.\epsilon_0.\frac{A}{d}$

k times the factor of permittivity of free space is the permittivity of the dielectric material.

Explanation:

Capacitance of an arrangement of a parallel plates capacitor having separation d having area A with a dielectric constant k permittivity of free space is $\epsilon_0$.

Then the capacitance is given:

$C=k.\epsilon_0.\frac{A}{d}$

• k times the factor of permittivity of free space is the permittivity of the dielectric material.

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TOPIC: dielectric

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