A parallelogram PQRS has two diagonals PR and QS are 20 cm and 28 cm respectively. The diagonals PR and QS bisect at point O . find the length of PO and QO
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GIVEN :- In diagonals PR and PQ, O is the mid point of PR and PQ (since PR and PS bisect at point O) and PR = 20 cm and QS = 28cm
Therefore, in diagonal PR,
PO = OR
therefore, PO + OR = PR
=>PO + PO = PR (since PO = OR)
=>2PO = PR
=>2PO = 20cm (since PR = 20cm)
=>PO = 10cm
Now, in diagonal QS,
QO = OS
therefore, QO + OS = QS
=>QO + QO = QS (since QO = OS)
=>2QO = QS
=>2QO = 28 cm (since QS = 28cm)
=>QO = 14cm
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