Question

a park 80 m by 65 m has a 3 m wide track all around it. a wall has been constructed around the track leaving a space for gate which is 2 m. what is the length of the outer boundary leaving the gate which has a wall? firnd tha perimeter of the park without track

Answer 1

Length AB = 40 m and breadth BC = 25 m

Area of lawn ABCD = 40 m x 25 m = 1000 m2

Length PQ = (40 + 2 + 2 ) m = 44 m

Breadth QR = ( 25 + 2 + 2 ) m = 29 m

Area of PQRS = 44 m x 29 m = 1276 m2

Now, Area of the path = Area of PQRS – Area of the lawn ABCD

= 1276 m2 – 1000 m2 = 276 m2

Rate of leveling the path = Rs. 8.25 per m2

Cost of leveling the path = Rs.( 8.25 x 276) = Rs. 2277

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Answer 2

Answer:

Step-by-step explanation:

Length of park with track=80+3=83

Breadth of park with track =65+3=68

Perimeter with track =2(l+b)

2(83+68)=2(151)=302

Length of wall =302-2(legnth of gate) =300m

Perimeter of park without track =2(l+b)=2(80+65)=2(145)=290

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