Question

a park 95m long and 80m wide has a path 5m wide running outside and all around it. find the area of the park​

Answer 1

Step-by-step explanation:

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Answer 2

Question:

A rectangular park is 95 m long and 80m wide. A path 5m wide running outside and all around it. Find the area of the park.

Answer:

• Area of the park = 7600 m²

• Area of the path = 9450 m²

Step-by-step explanation:

As from the given we know that the length of the park is 95 m whereas the breadth is 80 m respectively. So, for finding the area of the park we will find use the formula of area of rectangle that is length times breadth. Further more , if you likely to find the path area, you can find that one too.

Let's solve it :

Solution :

For area of the rectangular park.

Formula for Area :

${\boxed{\sf{Area \: of \: rectangle = Length \times breadth}}}$

$:\implies \sf Length \: (l) = 95 \: m$

$:\implies \sf Breadth \: (b) = 80 \: m$

Putting up the respective values, we get -

$\dashrightarrow\:\:\sf Area = L \times B$

$\dashrightarrow\:\:\sf Area = 95 \times 80$

$\dashrightarrow\:\:\sf Area = 7600$

$\dashrightarrow\:\: \underline{ \boxed{\sf Area \: of \: rectangle = 7600 \: {m}^{2} }}$

________________________

Now, For Area of the Path including the Area of the rectangular park.

We know that, the constructed path also got include in the breadth now , then

Area of the park with path,

$\bullet \: \:$ Length = length of the rectangular park + 2 × (width of the path)

$:\implies \sf length = 95 m + 2(5 m)$

$:\implies \sf length = 95 m + 10 m$

$:\implies \sf \purple{length = 105 m}$

$\bullet \: \:$ Breadth = width of the rectangular park + 2 × (width of the path)

$:\implies \sf breadth = 80 m + 2(5 m)$

$:\implies \sf breadth = 80 m + 10 m$

$:\implies \sf \purple{Breadth = 90 m}$

Therefore,

$:\implies \sf Length \: (l) = 105 \: m$

$:\implies \sf Breadth \: (b) = 90 \: m$

Putting up the respective values, we get -

$\dashrightarrow\:\:\sf Area = L \times B$

$\dashrightarrow\:\:\sf Area = 105 \times 90$

$\dashrightarrow\:\:\sf Area = 9450$

$\dashrightarrow\:\: \underline{ \boxed{\sf Area \: of \: path = 9450 \: {m}^{2} }}$