Math, asked by aaronaquin430, 8 months ago

a park charges rupees 10 for adults and rupees 5 for kids how many adults ticket and kids ticket were sold if a total of 548 tickets was sold for​

Answers

Answered by Anonymous
5

Let "x" be the number of adults tickets and "y" be the number of kids tickets.

No. of adults tickets + No. of kids tickets  =  Total

x + y  =  548 -------- (2)

Step 2 : 

Write an equation which represents the total cost.

Cost of "x" no. adults tickets  =  10x

Cost of "y" no. of kids tickets  =  5y

Total cost  =  $3750

Then, we have 

10x + 5y  =  3750

 Divide both sides by 5.

2x + y  =  750 -------- (2)

Step 3 :

Solve an equation for one variable.

Select one of the equation, say x + y  =  548.

Solve for the variable y in terms of x. 

Subtract x from both sides. 

(x + y) - x  =  (548) - x

y  =  548 - x

Step 4 : 

Substitute the expression for y in the other equation and solve.

2x + y  =  750

2x + (548 - x)  =  750

Combine like terms. 

x + 548  =  750

Subtract 548 from both sides.

x  =  202

Step 5 : 

Substitute the value of x we got above (x = 202) into one of the equations and solve for the other variable, y.

x + y  =  548

202 + y  =  548

Subtract 202 from both sides.

y  =  346

So, the solution of the system is (202, 346).

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