A park has a radius of 10 m. If a vehicle goes round it at an average speed of 18 km/hr, what should be the proper angle of banking?
Answers
Answered by
25
Given conditions ⇒
Radius of the Park = 10 m.
Average Speed = 18 km/hr = 5 m/s.
We know that the Angle of the Banking will be equal to the,
tanθ = v²/rg where θ is the angle of the Banking.
⇒ tanθ = v²/rg
⇒ tanθ = (5)²/10 × 10
⇒ tanθ = 0.25
∴ θ = tan⁻¹ (0.25)
∴ Proper angle of Banking is tan⁻¹ (0.25).
Hope it helps.
Answered by
7
The proper angle of banking is tan⁻¹ (0.25).
Explanation:
Given conditions:
Radius of the Park = 10 m.
Average Speed = 18 km/hr = 5 m/s.
We know that the Angle of the Banking will be equal to the,
tanθ = v²/rg where θ is the angle of the Banking.
⇒ tanθ = v²/rg
⇒ tanθ = (5)²/10 × 10
⇒ tanθ = 0.25
θ = tan⁻¹ (0.25)
Proper angle of Banking is tan⁻¹ (0.25).
Thus the proper angle of banking is tan⁻¹ (0.25).
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