A park is 25 - m long and 20- m wide. Find its perimeter. If a walkway is to be constructed inside the par
which is 2
m wide, what would be the inside perimeter of the walkway?
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Answer:
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Given : park is 25 - m long and 20- m wide . a walkway is to be constructed inside the par k which is 2 m wide
To find : Perimeter of Park
inside perimeter of the walkway
Solution :
Perimeter of Park = 2 ( Length + width)
= 2 ( 25 + 20)
= 2 ( 45)
= 90 m
a walkway is to be constructed inside the par k which is 2 m wide
Inside length = 25 - 2 * 2 = 21 m
inside width = 20 - 2 * 2 = 16 m
Inside perimeter = 2 ( 21 + 16 ) = 74 m
Actual Question is :
https://brainly.in/question/17466377
Park length 25 4/5 m = 25 + 4/5 m = (125 + 4)/5 = 129/5 m
Park Width = 20 2/3 m = 20 + 2/3 m = (60 + 2)/3 = 62/3 m
Park perimeter = 2 ( Length + Width )
= 2 ( 129/5 + 62/3)
= 2( 387 + 310)/15
= 2(697)/15
= 1394 / 15
= 92 14/15 m
walkway is to be constructed inside the park which is 2 3/8m wide
2 + 3/8 m = 19/8 Meter
8 times the width will be reduced
8 * 19/8 = 19 m
inside perimeter of the walkway = 92 14/15 - 19
= 75 14/15 m
Park perimeter = 92 14/15 m
inside perimeter of the walkway = 75 14/15 m
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