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abx²+aby²-xya²-xyb²=0
ax[bx-ay]+by[ay-bx]=0
ax[bx-ay]-by[bx-ay]=0
[ax-by][bx-ay]=0
ax=by
a/b=y/x
bx=ay
a/b=y/x
hence final result is a/b=y/x
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hey answer is in the attachment
hope it helps ☺️
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