Question

a park is in the form of a quadrilateral.one of its diagonal is 240 metre. the two vertices on either side is there diagonal is are 70 and 80.find the area of the park??​

Answer 1

Therefore area of 1 triangle

(1 side of the diagonal

Thus;

• a = 70m
• b = 80m
• c = 240m

$s \: = \frac{a + b + c}{2} \\ s \: = \frac{70 + 80 + 240}{2} \\ s \: = \frac{390}{2} \\ s \: = 195 \: m$

Thus using heron's formula;

$\sqrt { s(s-a)(a-b)(s-c) } = area$

∆ =

√{(240)(240-70)(240-80)(240-150)}

√{240 × 170 × 160 × 90}

√{587520000}

= 24238 approx.

#answerwithquality

#BAL

Answer 2

Answer:

Sarthak .

your answer is wrong

answer is 18000cm²