A park of length 150 m and breadth 80 m has a uniform path of width 5 m running all around the inside the remaining area is to be covered by grass find the cost of cementing the path at the rate of rupeds8.50 per m and grassing at the rate of rupees 2 per m
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I think you have made a mistake in writing the unit of rates i.e., it shall be in per square metre.
Solution:
Let us first find the
length of pathway = 150 + (80-5-5) + 150 + (80-5-5) = 440 m
& the area of the pathway = 440 x 5 = 2200 sq. m.
Therefore, the cost of cementing the pathway = 2200 x 8.50 = ₹18,700/-
Now, landscaping area = (150-5-5) x (80-5-5)
= 9800 sq. m.
Therefore, the cost of landscaping = 9800 x 2 = ₹19,600/-
Solution:
Let us first find the
length of pathway = 150 + (80-5-5) + 150 + (80-5-5) = 440 m
& the area of the pathway = 440 x 5 = 2200 sq. m.
Therefore, the cost of cementing the pathway = 2200 x 8.50 = ₹18,700/-
Now, landscaping area = (150-5-5) x (80-5-5)
= 9800 sq. m.
Therefore, the cost of landscaping = 9800 x 2 = ₹19,600/-
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Answer:
₹18700
₹19600
hope it will help you
bye
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