A parrot is sitting on the floor of a closed glass cage which is in boy's hand. If the parrot starts flying with constant speed, the boy will feel the weight of the cage as :
1. ) unchanged. 2.) reduced. 3.)increased.
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Answers
Answered by
51
If the cage is completely closed, it doesn't make a difference if the bird is hovering inside it or if it sits on the ground. When flying, the bird pushes air to the ground which will exert a downward force on the cage exactly equal to the weight of the bird. This is a direct consequence of the conservation of momentum and Newton's second & third law. Since no additional external force is acting on the cage-bird-system when the bird is flying as compared to when it's not, the acceleration on the cage can be no different. The effect due to the flying bird only concerns the internal forces and since action=reaction, they cancel.
However, if the cage would not be closed, some of the 'wind' due to the bird could escape the cage and would become an external force, making the cage-bird-system lighter.
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However, if the cage would not be closed, some of the 'wind' due to the bird could escape the cage and would become an external force, making the cage-bird-system lighter.
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Answered by
8
If the parrot starts flying then the weight of the glass cage is reduced.
Explanation:
The weight will only be reduced in the case when the cage is so large as when parrot try to fly. It does not have its legs on the floor of the glass cage.
If the glass cage is small and parrot try to fly. It does not leave the floor. there will be no change in the weight.
only some shakings may be felt that may lead to slight reduce ar a slight increase in weight.
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