Question

A part of monthly expenses of a family on milk is fixed for ₹ 500 and the remaining varies with the quantity of the milk, taken extra at the rate of ₹ 20 per kg. Taking the quantity of milk required extra as x kg and the total expenditure on milk is ₹ y, write a linear equation for this information and draw its graph.

Answer 1

Step-by-step explanation:

Question :-

• A part of monthly expenses of a family on milk is fixed for ₹ 500 and the remaining varies with the quantity of the milk, taken extra at the rate of ₹ 20 per kg. Taking the quantity of milk required extra as x kg and the total expenditure on milk is ₹ y, write a linear equation for this information and draw its graph.

Given :-

• A part of monthly expenses of a family on milk is fixed for ₹ 500.
• the remaining varies with the quantity of the milk, taken extra at the rate of ₹ 20 per kg.
• Taking the quantity of milk required extra as x kg .
• the total expenditure on milk is ₹ y,

To Find :-

• write a linear equation for this information and draw its graph.

Solution :-

If The quantity of extra milk be 'x' kg and expenditure be 7'y then according to the given condition,

y = 20x + 500

(As ? 500 is the fixed expenditure)

Put x = 0 in equation (i)

y = 20(0) + 500

y = 500

Put y = 1000 in equation (i)

1000 = 20x + 500

1000 - 500 = 20x

500 = 20x

x = 500/20

x = 25 kg

Put x = 2 in equation (i)

y = 20(2) + 500

y = 40 + 500

y = 540

Hence the x is 25 kg and y is 540

Answer 2

Answer:

20x-y+500=0

Step-by-step explanation:

Fixed part = Rs. 500

Cost of extra milk = Rs. 20 / litre

Total extra milk reqd. = x litres

Total expenditure = Rs. y

Equation formed is,

500+20x=y

=> 20x-y+500=0

GRAPH IN FIG.

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