A part of monthly expenses of a family on milk is fixed for ₹ 500 and the remaining varies with the quantity of the milk, taken extra at the rate of ₹ 20 per kg. Taking the quantity of milk required extra as x kg and the total expenditure on milk is ₹ y, write a linear equation for this information and draw its graph.
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hey mate look at the attachment. ......✌✌
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Answered by
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Answer:
20x-y+500=0
Step-by-step explanation:
Fixed part = Rs. 500
Cost of extra milk = Rs. 20 / litre
Total extra milk reqd. = x litres
Total expenditure = Rs. y
Equation formed is,
500+20x=y
=> 20x-y+500=0
GRAPH IN FIG.
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