Math, asked by Rndy2004, 7 months ago

A part of monthly expenses of a family on milk is fixed for ₹ 500 and the remaining varies with the quantity of the milk, taken extra at the rate of ₹ 20 per kg. Taking the quantity of milk required extra as x kg and the total expenditure on milk is ₹ y, write a linear equation for this information and draw its graph.

Answers

Answered by jisso30
5

hey mate look at the attachment. ......✌✌

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Answered by Anonymous
0

Answer:

20x-y+500=0

Step-by-step explanation:

Fixed part = Rs. 500

Cost of extra milk = Rs. 20 / litre

Total extra milk reqd. = x litres

Total expenditure = Rs. y

Equation formed is,

500+20x=y

=> 20x-y+500=0

GRAPH IN FIG.

HOPE IT HELPS,

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