A partially dried clay mineral contains 8% water.The original sample contained 12% water and 45% silica.The % of silica in the partially dried sample in nearly :
(a) 50% (b) 49% (c) 55% (d) 47%
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(d) 47%
Explanation:
Let the sample be 100 g
Original sample: 12 g of water and 45 g of silica
Dried sample : 8 g of water and x g of silica.. Total weight of dried sample becomes =96 g now
Percentage of silica in dried sample = (45/96)*100 =46.87 %
approximately 47 % of silica is present in partially dried sample
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