Question

a Partical has displacement of 12 m towards east and 5 m towards north then 6 m vertically upward. the sum of these displacement is

Answer 1

think of 3d space here

thus: resultant displacement will be sqrt(12^2+5^2+6^2)

= sqrt(205)

=14.32

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Mann02
Helping Hand

Answer 2

If unit vectors along east, noth and upwards are taken as i, j and k respectively then,

Displacement = (12i + 5j + 6k) m

Magnitude of displacement = √(12² + 5² + 6²) = 14.31 m