Question

a partical starts moving along a circle of radius 20/πm with a constant tangential acceleration.if the velocity of the partical is 50 m/s at the end of the second revolution after the motion has began,the tangential acceleration in m/s2 is:​

Answer 1

Answer:

Answer

r=π20

In two revolution , distance is s=2×2πr=80m

Now, v2=2as for zero initial speed.

⟹a=2sv2=2×8080×80

⟹a=40m/s2

Answer 2

Answer:

a = 15.625 m/s²

Explanation:

r = $\frac{20}{\pi }$ m

v = 50 m/s

θ = 2 revolutions = 4π rad.

Using Equation :

ω² = ω₀² + 2αθ     ..(ω₀=0)

ω² = 2αθ     ..(ω=v/r  &  a=rα)

a = v²/2rθ

a = 2500π/160π

a = 15.625 m/s²