Question

A particle a moving with certain velocity has de broglie wavelength of 1 angstrom.For particle b with mass 25% if a and velocity 75% og a calculate the de broglie wavelength

Answer 1

Answer:

5.33A°

Explanation:

lambda A=1A°=10^-10m

mB=25℅ of mA

mB=1/4×mA

vB=75/100×vA=3/4×vA

lambda A=h/mA.vA

mA.vA=h/10^-10m

lambda B=h/mB.vB

lambda B=h/(mA/4×3/4vA)

lambda B=(16/3)h/h×10^-10

lambda B=5.33×10^-10m

lambda B=5.33A°