Divide 47 among A B and C so that A gets rupees 10 more than B and B has rupees 8 more than c
Answers
Answered by
8
let c=x
so,47=a+b+c
47=x+{x+8}+(x+8)+10
because it is given that c+8=b and b+10 =a
47=3x+26
3x=21
x=7
so,c=7
b=7+8=15
a=15+10=25
so,47=a+b+c
47=x+{x+8}+(x+8)+10
because it is given that c+8=b and b+10 =a
47=3x+26
3x=21
x=7
so,c=7
b=7+8=15
a=15+10=25
Answered by
0
a = 25 is the answer...
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