A particle absorbs a photon of 300nm and remits the energy jn the form of 2 photons if the Wavelength of one photon is 700nm then what will be the Wavelength of another photon
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Heya mate
The answer of ur question is in pic
The answer of ur question is in pic
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Solution :
Ephoton absorbed=E1+E2Ephoton absorbed=E1+E2(energy released)
hCλ=hCλ1+hCλ2hCλ=hCλ1+hCλ2
⇒1λ=1λ1+1λ2⇒1λ=1λ1+1λ2
⇒1300nm=1600nm+1λ2⇒1300nm=1600nm+1λ2
∴λ2=600×300600−300∴λ2=600×300600−300
=1800300=1800300=600
PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER.
Ephoton absorbed=E1+E2Ephoton absorbed=E1+E2(energy released)
hCλ=hCλ1+hCλ2hCλ=hCλ1+hCλ2
⇒1λ=1λ1+1λ2⇒1λ=1λ1+1λ2
⇒1300nm=1600nm+1λ2⇒1300nm=1600nm+1λ2
∴λ2=600×300600−300∴λ2=600×300600−300
=1800300=1800300=600
PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER.
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