a particle along a circle of radius = 1 m so that its radius vector r relative to a point on its circumference rotates with constant angular velocity= 2 rads/s the linear speed of particle is?
pls solve fast urgent
Answers
Answered by
0
R=0.50 m,
ω=0.40 rad/s
θ=θ'/2
ω'=2ω
v'=2ωR=.40m/s
a=ω2R
a'=ω'2R=(2ω)2R=4ω2R=.32m/s2
ω=0.40 rad/s
θ=θ'/2
ω'=2ω
v'=2ωR=.40m/s
a=ω2R
a'=ω'2R=(2ω)2R=4ω2R=.32m/s2
rahulmandviya:
r u sure??
Answered by
1
V = Rω
V = 1×2
V = 2m/s
V = 1×2
V = 2m/s
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