Physics, asked by Mindblowing, 1 year ago

a particle at rest starts motion with uniform acceleration graph between kinetic energy and displacement is
(a) straight line
(b) symmetric parabola
(c)asymmetric parabola
(d)elliptical
and expalin it?

Answers

Answered by KartikSharma13

Ofcourse
(b) symmetric parabola

Mindblowing: can you explain it please

KartikSharma13: Kinetic energy of a particle executing S.H.M is given by, Potential energy is given by, Therefore the graph forkinetic energy versus displacement is a symmetrically parabola, which is shown below. Thegraph for potential energy versusdisplacement is also symmetric parabola.

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Answered by DeenaMathew

The graph between kinetic energy and displacement is (a) a straight line.

According to the equation of motion v = u + at.
u is 0. so, v = at.
Now, s = ut + 1/2at². v is velocity, s is distance and a is acceleration.
$s = \frac{1}{2} at²$
$Kinetic \: energy = \frac{1}{2} mv² = \frac{1}{2}m {(at)}^{2} = \frac{1}{2}m {(t)}^{2} {a}^{2}$
Now, replacing 1/2at² by distance(s).
$kinetic \: energy = mas$
So, kinetic energy is directly proportional to distance.
Hence, the graph between kinetic energy and displacement is a straight line.