Question

A particle completes half a round of a circular path of radius 28 cm. What is the distance travelled and displacement of the particle? ​

Answer 1

Explanation:

For completing the half round of circle, the distance covered will be half of circumference of the circle i.e., d=πR.

Displacement is the shortest distance between initial and final position, so the displacement will be just the diameter of circle. S=2R

Answer 2

Provided that: A particle completes half a round of a circular path of radius 28 cm.

To calculate: Distance travelled and displacement by the particle.

Solution: Distance travelled by the particle is 88 cm and displacement is 56 cm.

Using concepts:

• Distance travelled in a circle for half round.

• Displacement covered in a circle for half round.

Using formulas:

• Distance travelled in a circle for half round is mentioned below:

• ${\small{\underline{\boxed{\pmb{\sf{\pi \: r}}}}}}$

• Displacement covered in a circle for half round is mentioned below:

• ${\small{\underline{\boxed{\pmb{\sf{2r}}}}}}$

Where, r denotes radius of circle.

Knowledge required:

• Displacement is the shortest distance between the initial and final position.

Required solution:

~ Firstly calculating distance travelled!

→ Distance = πr

→ Distance = 22/7 × 28

→ Distance = 22 × 4

→ Distance = 88 cm

• Henceforth, distance = 88 cm.

~ Now let us find out the displacement!

→ Displacement = 2r

→ Displacement = 2 × 28

→ Displacement = 56 cm

• Henceforth, displacement = 56 cm.