a particle covers (3/4) th of a circle of radius R.the distance and displacement of particle will be ?
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I am very really sorry
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so so sorry I don't know
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GIVEN:
A particle covers 3/4 th of a circle
TO FIND:
Distance=?
Displacement=?
SOLUTION:
DISTANCE IS THE ACTUAL DISTANCE COVERED BY THE OBJECT
Distance=3/4×2πR
Distance=1.5 π R
DISPLACEMENT IS THE SHORTEST DISTANCE BETWEEN THE INITIAL AND FINAL POSITION
Displacement=√(R)²+(R)²
Displacement=√2R
I hope this helps ( ╹▽╹ )
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