Question

A particle covers 50 m. distance with 40 kmph and rest half
distance with 60 kmph then the average speed of car is:

Answer 1

Answer:

Explanation:

T1= 25×18/40×5. { Converting into m/s and then proceeding}

T2= 25×18/60×5

Total time= 15/4 sec

Then, v(avg)= dist/total time

Answer 2

The average speed of car is 48.09 km/h.

Explanation:

A particle covers 50 m distance with 40 km/h and rest 50 m with 60 km/h. We need to find the average speed of car. We know that the average speed of any object is equal to total distance divided by total time taken. It is given by :

$v=\dfrac{d}{t}$

Total distance covered by the car is 100

When the particle covers 50 m distance with 40 km/h, time taken by it is,

v = 40 km/h = 11.12 m/s

$t_1=\dfrac{50}{11.12}=4.49\ s$

When the particle covers remaining 50 m distance with 60 km/h, time taken by it is,

v = 60 km/h = 16.67 m/s

$t_2=\dfrac{50}{16.67}=2.99\ s$

Average speed,

$v=\dfrac{2d}{t_1+t_2}$

$v=\dfrac{2\times 50}{4.49+2.99}$

v = 13.36 m/s

or

v = 48.09 km/h

So, the average speed of car is 48.09 km/h. Hence, this is the required solution.

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