Question

A particle describes a semicircle of radius 14 M what are its distance and displacement covered

Answer 1

As initial and the final positions coincide the displacement = 0
Distance is the sum of the half of the perimeter and the diameter
Distance = Half of the perimeter + Diameter
Distance = [(22/7)×14 + 2 ×14 ] m
Distance = (44 + 28)m
Distance = 72 m.