Question

A particle displacement S along x-axis varies with time T according to relation s= 2(1-2t)t the velocity of the particle when it return to its initial point of a start is

Answer 1

Solution –

s = 2(1 - 2t)t
s = (2 - 4t) t
s = 2t - 4t²
v = d(s)/dt
$v = \: \frac{d \: (2t - 4 {t}^{2} )}{dt}$
v = (2 - 8t) m/s