A particle executes S.H.M with a time period of 2S and amplitude 5 cm. Find
al Displacement b) Velocity
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Answer: y =5sin(πt)
v = 5π cos(πt)
Explanation:
Given that,
Time period(T) = 2 seconds
Amplitude(a) = 5 cm
Since the particle executes SHM,
Phase(Ф) = 0
We know that equation of displacement of particle in SHM is,
Differentiating this equation with respect to t,
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