Question

formula y= mgl/pi r ^2l Is given if mg is doubled ,what is the young modules ?

Answer 1

Answer:

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress.

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] and

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS =

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L]

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT −2

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT −2 ][L]

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT −2 ][L]

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT −2 ][L] −1

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT −2 ][L] −1 T

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT −2 ][L] −1 T −2

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT −2 ][L] −1 T −2 ]

Young's modulus Y= stress/strain. Stress =Force/area and strain =increase in length/ original length So strain is dimensionless. Thus, Y will have dimension equal to stress. The dimension of LHS =[Y]=[ML −1 T −2 ] andThe dimension of RHS = [L 2 ][L][M][LT −2 ][L] −1 T −2 ]As the dimension of LHS is same as the dimension of RHS so the given equation is dimensionally correct.

Answer 2

Answer:

The formula Y = mgL/πr²l is given. If mg is doubled, the young modulus will remain the same i.e Y.

Explanation:

• The ratio of tensile stress to tensile strain is known as the Young's modulus (Y), a feature of the material that indicates how easily it can stretch and flex. Where strain is extension per unit length ( = dl/l) and stress is the amount of force applied per unit area ( = F/A).
• The ratio of longitudinal stress to longitudinal strain is known as Young's modulus.
• It is mathematically expressed as Y = longitudinal stress / longitudinal strain
• It can also be expressed by the formula - Y = MgL/πr²l where, Mg = load, l/L = longitudinal strain, πr² = area of cross-section
• Young's modulus values are influenced by the composition of the material.
• It measures elastic stiffness.
• It is not dependent on either the cross-section or the load applied.
• Even if the load is doubled, the young modulus will remain the same i.e Y.

Thus, in a given formula of y= mgL/πr²l if mg is doubled the young modulus will remain the same i.e Y.

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