Question

A particle executes SHM about the origin
along y-axis. At y= 1m, the potential
energy of the particle is equal to its kinetic
energy. Its amplitude of oscillation is​

Answer 1

Answer:

Potential energy (U)=  

2

1

​  

kx  

2

 

Kinetic energy (K)=  

2

1

​  

kA  

2

−  

2

1

​  

kx  

2

 

According to the question, U=k

∴  

2

1

​  

kx  

2

=  

2

1

​  

kA  

2

−  

2

1

​  

kx  

2

 

x=±  

2

​  

 

A

​

Explanation:

Potential energy (U)=  

2

1

​  

kx  

2

 

Kinetic energy (K)=  

2

1

​  

kA  

2

−  

2

1

​  

kx  

2

 

According to the question, U=k

∴  

2

1

​  

kx  

2

=  

2

1

​  

kA  

2

−  

2

1

​  

kx  

2

 

x=±  

2

​  

 

A

​