A particle executing S.H.M. has period 3 sec and amplitude 4 cm. The time it will take to travel from its position of maximum displacement to one corresponding to half its amplitude is
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Answered by
5
Answer:
0.5 sec
Explanation:
given :
time period= 3sec
amplitude= 4 cm
cos° =A/2/A
° = π/3 = 2π/T *t
t= π/6 =3/6 = 0.5 sec
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Answered by
1
Answer:
your answer is 0.5 second
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